Operator precedence: what happens when statement *a++ is executed?

Consider a function that copies content of array a into array v:

void func_copy(int n, double  *a, double *v){
    for(int i=0; i < n; i++) v[i] = *a++;
}

Statement *a++, according to C/C++ operator precedence table, is interpreted as:

*(a++)

so that the pointer is incremented before de-referencing. However, since we have a post-increment operator here (pre-increment would be ++a), the actual sequence is:

  • Save current value pointed by the pointer
  • Increment the pointer
  • Do de-referencing using the saved previously value
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